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Resistance of a conductor of length l an...

Resistance of a conductor of length l and area of cross-section A is R. If its length is doubled and area of cross-section is halved, then find its new resistance.

Text Solution

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Initial length = I, Area = A
So , initial resistance ` R = rho (l)/(A)`
Final length l = 2l , Area A ` = (A)/(2)`
New resistance ` R = rho (l)/(A) = rho (2l)/((A)/(2)) = 4rho (l)/(A) = 4R`
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