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The potential difference applied to an X...

The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. Then the number of electros striking the target par second is

A

`2 xx 10^(16)`

B

`5xx 10^(16)`

C

`1 xx 10^(17)`

D

`4 xx 10^(15)`

Text Solution

Verified by Experts

The correct Answer is:
A
`I = ("ne")/(t) . (n)/(t) = 2 xx 10^(16)`
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