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There is a current of 40 ampere in a wir...

There is a current of 40 ampere in a wire of `10^(-6)m^(2)` are of cross-section. If the number of free electron per `m^(3)` is `10^(29)` then the drift velocity will be

A

`1.25 xx 10^(3)` m/s

B

`2.5 xx 10^(-3)` m/s

C

`25 xx 10^(-3)` m/s

D

`25 xx 10^(3)` m/s

Text Solution

Verified by Experts

The correct Answer is:
B
`v_(d) = (1)/("ne" A)`
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