Home
Class 12
PHYSICS
If n, e, tau, m, are representing electr...

If n, e, `tau`, m, are representing electron density charge, relaxation time and mass of an electron respectively then the resistance of wire of length 1 and cross sectional area A is given by

A

`(ml)/("ne"^(2) tau A)`

B

`( m tau A)/("ne"^(2) l)`

C

`("ne"^(2) tau A)/(ml)`

D

`("ne"^(2) A)/(m tau l)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The resistance will be least in a wire with length, cross-section area respectively,

If the free electron density be n and relaxation time be tau , the electrical conductivity of a conductor may be expressed as

If n ,e,m and tau are free electron density in conductor , charge of electron, mass of electron and relaxation time of free electrons , then resistivity rho of the conductor can be expressed as

The speed of transverse waves in a wire of length L , density rho , cross - sectional area A and stretched with a tension T is given by

If two conducting wires Aand B of same dimensions have electron density ratio 1: 3 . If their relaxation time is same then the ratio of resistance of A to resistance of B is

If in a conductor number density of electrons is 8.5xx10^(28) average relaxation time 25 femtosecond mass of electron being 9.1xx10^(-31) kg, the resistivity would be of the order.