Home
Class 12
PHYSICS
The true value of dip at a place is 30^(...

The true value of dip at a place is `30^(@)` . The vertical plane carrying needle is turned through `30^(@)` from magnetic meridian . Calculate apparent value of angle of dip .

Text Solution

Verified by Experts

`tan del _(A) = (tan del )/( cos alpha )`
` tan del _(A) = (tan 30^(@))/(cos 30^(@))= ((1)/(sqrt3))/((sqrt3)/(2))`
`tan del _(A) = 2/3`
`del _(A) = tan ^(-1) ((2)/(3)).`
Promotional Banner

Similar Questions

Explore conceptually related problems

The true value of dip at a place is 30^(@) . The vertical plane carrying the needle is turned through 45^(@) from the magnetic meridian . Calculate the apparent value of dip .

The true value of dip at a place is 45^@ . If the vertical plane carrying the needle is turned through 60^@ from the magnetic meridian, find the inclination of the needle (i.e. what will be the apparent value of dip)?

The value of dip at a place is 45^@ . The plane of the dip circle is turned through 60^@ from the magnetic meridian. Find the apparent value of dip.

The true value of angle of dip at a place is 60^(@) . The apparent angle of dip , when a magnetic needle is rotated through 30^(@) from the magnetic meridian at the same place , is

The true value of angle of dip at a place is 60^(@) , the apparent dip in a inclined at an angle of 30^(@) with magnetic meridian is

The true dip at a place is 30^(@) . What is the apparent dip when the dip circle is turned 60^(@) out of the magnetic meridian ?

The true dip at a place is 30^@ . In what plane is the dip apparently 60^@ ?

The angle of dip at a place is delta . If the dip is measured in a plane makinng an angle theta with the magnetic merdian, the apparent angle of dip delta_(1) will be