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A short bar magnet is kept in uniform ma...

A short bar magnet is kept in uniform magnetic field of `0.16T` such that dipole moment vecotor is at angle `30^(@)` with the field. The torque acting on the bar magnet is `0.032` N m. What is magnitude of magnetic dipole moment of the magnet ?

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To find the magnitude of the magnetic dipole moment (\(m\)) of the bar magnet, we can use the formula for torque (\(\tau\)) acting on a magnetic dipole in a magnetic field: \[ \tau = m \cdot B \cdot \sin(\theta) \] Where: - \(\tau\) is the torque, ...
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A short bar magnet is kept in uniform magnetic field of 0.16 T such that dipole moment vector is at angle 30^(@) with the field . The torque acting on the bar magnet is 0.032 N m . What is the magnitude of magnetic dipole moment of the magnet ?

What is the direction of the magnetic dipole moment in a bar magnet?

Knowledge Check

  • A magnetic dipole of moment M is placed in uniform magnetic field B so that angle betweem direction of M and B is theta ,the torque acting on the magnetic dipole is

    A
    MB `sintheta`
    B
    MB`tantheta`
    C
    MB `costheta`
    D
    MB

  • A small bar magnet of moment M is placed in a uniform field H. If magnet makes an angle of 30^(@) with field, the torque acting on the magnet is

    A
    `MH`
    B
    `(MH)/2`
    C
    `(MH)/3`
    D
    `(MH)/4`

  • The torque acting on a magnetic dipole of moment P_(m) when placed in a magnetic field is

    A
    `P_(m)B`
    B
    `vec(P_(m))xxvec(B)`
    C
    `vec(P_(m)).vec(B)`
    D
    `P_(m)//B`

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