A short bar magnet is kept in uniform magnetic field of `0.16T` such that dipole moment vecotor is at angle `30^(@)` with the field. The torque acting on the bar magnet is `0.032` N m. What is magnitude of magnetic dipole moment of the magnet ?

Explanation

To find the magnitude of the magnetic dipole moment (\(m\)) of the bar magnet, we can use the formula for torque (\(\tau\)) acting on a magnetic dipole in a magnetic field:

\[ \tau = m \cdot B \cdot \sin(\theta) \]

Where:
- \(\tau\) is the torque,
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