Home
Class 12
PHYSICS
A magnetising field of 1500""(A)/(m) pro...

A magnetising field of `1500""(A)/(m)` produces a magnetic flux density of `0.48 Wb//m^(2) ` in a iron bar . Calculate permeability of iron bar used .

Text Solution

Verified by Experts

`mu = (B)/(H) = (0.48)/( 1500)`
`= (48 xx 10 ^(-2))/( 15 xx 10 ^(2))`
` =(48)/(15) xx 10 ^(-4) (Wb)/(m ^(2)) xx (m)/(A)`
` = 3.2 xx 10 ^(-4) Wb//mA`
Promotional Banner

Similar Questions

Explore conceptually related problems

A magnetising field of 2xx10^(3)Am^(-1) produces a magnetic flux density of 8piT in an iron rod. The relative permeability of the rod will be

A magnetising field intensity of 1000 A/m produces a magnetic flux density 0.25 (Wb)/ m^2 in a ferromagnetic substance. The relative permeability of ferromagnetic substance is (Approximately)

A magnetising field of 360 Am^(-1) produces a magnetic flud density (B) =0.6 T in a ferromagnetic material what is its permeability in TmA^(-1) ?

A magnetising field of 1600 A/m produces a magnetic flux of 2.4 xx 10^(-5)Wb in a bar of iron of cross section 0.2"cm"^(2) . Then permeability of the bar is the equator

A magnetic field of 1600Am^-1 produces a magnetic flux of 2*4xx10^-5 weber in a bar of iron of cross section 0*2cm^2 . Calculate permeability and susceptibility of the bar.

A magnetizing field of 5000 A/m produces a magnetic flux of 5 xx 10^(-5) Wb in an iron rod of 0.5 cm^(2) area of cross-section. The permeability of the rod is (in Wb A^(-1) m^(-1) )

A magneting field of 1600 Am^(-1) produces a magnetic flux of 2.4xx10^(-5) wb in an iron bar of cross-sectional area 0.2cm^(2) .Calculate the permeability and susceptibility of the bar.

A magnetising field of 5000 A//m produces a magnetic flux of 5xx10^(-5) weber in an iron rod. If the area of cross section of the rod is 0.5 cm^(2) , then the permeability of the rod will be

A magnetising field of 5000 A/m produces a magnetic flux of 5xx10^(-5) weber in an iron rod. If the area of cross section of the rod is 0.5cm^(2) , then the permeability of the rod will be