Home
Class 12
PHYSICS
A magnetising field of 1600 Am^(-1) prod...

A magnetising field of `1600 Am^(-1)` produces a magnetic flux `2.4 xx 10^(-5)` weber in an iron bar of cross-sectional area `0.2 cm^(2)` . The susceptibility of the iron bar will be

A

1788

B

1192

C

596

D

298

Text Solution

Verified by Experts

The correct Answer is:
C
`mu = B/H = (phi)/(AH)`
` = (2.4 xx 10 ^(-5))/(0.2 xx 10 ^(-4) xx 16 xx 10 ^(2))`
`= (2.4 xx 10 ^(-5))/(16 xx 2 xx 10 ^(-3))`
` = (1.2)/(16) xx 10 ^(-2)`
` = 3/4 xx 10 ^(-3)`
` = 0.75 xx 10 ^(-3) Wb//mA`
`mu _(r) = (0.75 xx 10 ^(-3))/( 4 pi xx 10 ^(-7))`
` mu _(r) = (75)/(4pi) xx 10 ^(2)`
` = 5.9713376`
`mu _(r) = 597`
` x _(m) = mu_(r) -1`
`x _(m) = 597 -1`
` x _(m) = 596`
Promotional Banner

Similar Questions

Explore conceptually related problems

If a magnetising field of 1600 A//m produces a magnetic flux of 14xx10^(-5) Wb in an iron bar of cross-sectional area 0.2 cm^(2) . Then,

A magneting field of 1600 Am^(-1) produces a magnetic flux of 2.4xx10^(-5) wb in an iron bar of cross-sectional area 0.2cm^(2) .Calculate the permeability and susceptibility of the bar.

A magnetising field fo 1000 A/m produces a magnetics flux of 2.4 xx10^(-5) Wb in an iron bar of cross sectional area 0.3 cm^(2) what is the magnetic permeability of the iron bar ?

A magnetising field of 1600 A/m produces a magnetic flux of 2.4 xx 10^(-5)Wb in a bar of iron of cross section 0.2"cm"^(2) . Then permeability of the bar is the equator

A magnetic field of 1600Am^-1 produces a magnetic flux of 2*4xx10^-5 weber in a bar of iron of cross section 0*2cm^2 . Calculate permeability and susceptibility of the bar.

A magnetising field produces a magnetic flux of 2.2 xx 10^(-5) weber in an iron bar of cross section 0.5 cm^(2) what is the magnetic iduction ?

A magnetising field produces a magnetic flux of 2.2xx10^(-5) weber in an iron bar of cross section 0.5 cm^(2) . What is the magnetic induction?

A magnetising field of 1500 A//m produces a flux of 2*4xx10^-5 weber in a bar of iron of cross-sectional area 0*5cm^2 . Calculate the permeability and susceptibility of the iron bar used.

A magnetising field of 5000 A/m produces a magnetic flux of 5xx10^(-5) weber in an iron rod. If the area of cross section of the rod is 0.5cm^(2) , then the permeability of the rod will be