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The magnetic moments of two bar magnets ...

The magnetic moments of two bar magnets of same size are in the ratio `1:2.` When they are placed one over the other with their similar poles together, then their perlod of oscillation in a magnetic field is 3s. If one of the magnets is reversed, then the period of oscillation in the same field will be q

A

`sqrt3s`

B

`3sqrt3s`

C

`3 s`

D

`6 s`

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To solve the problem, we will follow these steps: ### Step 1: Define the Magnetic Moments Let the magnetic moments of the two bar magnets be: - \( m_1 = x \) (for the first magnet) - \( m_2 = 2x \) (for the second magnet) ### Step 2: Calculate the Resultant Magnetic Moment When Similar Poles Are Together When both magnets are placed with their similar poles together (i.e., north-north or south-south), the resultant magnetic moment \( m_3 \) is the sum of the individual magnetic moments: \[ m_3 = m_1 + m_2 = x + 2x = 3x \] ### Step 3: Write the Expression for the Period of Oscillation The period of oscillation \( T \) for a magnetic moment in a magnetic field is given by the formula: \[ T = 2\pi \sqrt{\frac{I}{mB}} \] where: - \( I \) is the moment of inertia, - \( m \) is the magnetic moment, - \( B \) is the magnetic field strength. Given that the period of oscillation when similar poles are together is \( T = 3 \, \text{s} \), we can write: \[ 3 = 2\pi \sqrt{\frac{I}{3xB}} \tag{1} \] ### Step 4: Calculate the Resultant Magnetic Moment When One Magnet Is Reversed When one of the magnets is reversed, the resultant magnetic moment \( m_4 \) is the difference of the two magnetic moments: \[ m_4 = m_2 - m_1 = 2x - x = x \] ### Step 5: Write the Expression for the New Period of Oscillation Now, we can write the expression for the period of oscillation when one magnet is reversed: \[ T' = 2\pi \sqrt{\frac{I}{xB}} \tag{2} \] ### Step 6: Take the Ratio of the Two Periods To find the new period \( T' \), we can take the ratio of equations (2) and (1): \[ \frac{T'}{T} = \sqrt{\frac{3xB}{3xB}} = \sqrt{3} \] Thus, \[ T' = T \cdot \sqrt{3} = 3 \cdot \sqrt{3} \, \text{s} \] ### Final Answer The period of oscillation when one of the magnets is reversed is: \[ T' = 3\sqrt{3} \, \text{s} \] ---
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AAKASH INSTITUTE-MAGNETISM AND MATTER -ASSIGNMENT (SECTION A)
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