In a p-n junction having depletion layer of thickness `10^(-6)` m the potential across it is `0.3 V`. Then the electric field is
Hint = `E= V/d`

Options

A. `10^(-5) V/m`
B. `3xx 10^(5) V/m`
C. `10^(-6) V/m`
D. `3 xx 10^(7) V/m`

Answer

To find the electric field (E) across a p-n junction depletion layer, we can use the formula:

\[ E = \frac{V}{d} \]

where:
- \( E \) is the electric field,
- \( V \) is the potential across the depletion layer,
- \( d \) is the thickness of the depletion layer.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Potential (V) = 0.3 V
- Thickness of the depletion layer (d) = \( 10^{-6} \) m

2. **Substitute the Values into the Formula:**
\[ E = \frac{0.3 \, \text{V}}{10^{-6} \, \text{m}} \]

3. **Calculate the Electric Field:**
- First, calculate the division:
\[ E = 0.3 \times 10^{6} \, \text{V/m} \]
- This simplifies to:
\[ E = 3 \times 10^{5} \, \text{V/m} \]

4. **Final Result:**
The electric field across the depletion layer is:
\[ E = 3 \times 10^{5} \, \text{V/m} \]