In a transitor `(Beta = 50)`, the voltage across `5 kOmega` load resistance in collector circuit is `5V`. The base current is

Options

A. `0.02 mA`
B. `0.03 mA`
C. `0.08 mA`
D. `0.09 mA`

Answer

To find the base current (IB) in the transistor circuit, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values:**
- Beta (β) = 50
- Load resistance (RL) = 5 kΩ = 5000 Ω
- Voltage across the load resistance (Vc) = 5 V

2. **Calculate Collector Current (IC):**
- The relationship between voltage, current, and resistance is given by Ohm's Law:
\[ V = I \times R \]
- Rearranging this for current (I) gives:
\[ I = \frac{V}{R} \]
- Here, we can calculate the collector current (IC) as:
\[ IC = \frac{Vc}{RL} = \frac{5V}{5000Ω} = 0.001 A = 1 mA \]

3. **Use the Relationship Between Collector Current and Base Current:**
- The relationship between collector current (IC) and base current (IB) is given by:
\[ β = \frac{IC}{IB} \]
- Rearranging this formula to find IB gives:
\[ IB = \frac{IC}{β} \]

4. **Substitute the Values:**
- Now, substituting the values we have:
\[ IB = \frac{1 mA}{50} = \frac{0.001 A}{50} = 0.00002 A = 0.02 mA \]

5. **Final Answer:**
- Therefore, the base current (IB) is:
\[ IB = 0.02 mA \]