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The input signal given to a CE amplifier...

The input signal given to a CE amplifier having a voltage gain of 150 is `V_(1) = 2cos(15t + pi/3)`. The corresponding output signal will be

A

`300cos(15t + 4pi/3)`

B

`300 co(15t + pi/3)`

C

`75 cos(15t + 2pi/3)`

D

`2cos(15t + 5pi/6)`

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The correct Answer is:
To solve the problem, we need to determine the output signal of a common emitter (CE) amplifier given the input signal and the voltage gain. Let's break it down step by step. ### Step 1: Identify the Input Signal and Voltage Gain The input signal is given as: \[ V_{in} = 2 \cos(15t + \frac{\pi}{3}) \] The voltage gain (A) of the amplifier is given as: \[ A = 150 \] ### Step 2: Calculate the Maximum Output Voltage The maximum value of the input voltage, \( V_{in(max)} \), is the amplitude of the input signal, which is 2V. The maximum output voltage can be calculated using the formula: \[ V_{out(max)} = A \times V_{in(max)} \] Substituting the values: \[ V_{out(max)} = 150 \times 2 = 300V \] ### Step 3: Determine the Phase Shift In a common emitter amplifier, there is a phase shift of \( \pi \) (or 180 degrees) between the input and output signals. Therefore, if the input signal has a phase of \( \frac{\pi}{3} \), the output signal will have a phase of: \[ \text{Phase of } V_{out} = \text{Phase of } V_{in} + \pi = \frac{\pi}{3} + \pi = \frac{\pi}{3} + \frac{3\pi}{3} = \frac{4\pi}{3} \] ### Step 4: Write the Output Signal Now, we can express the output signal using the maximum output voltage and the phase shift: \[ V_{out} = V_{out(max)} \cos(15t + \text{Phase of } V_{out}) \] Substituting the values we found: \[ V_{out} = 300 \cos(15t + \frac{4\pi}{3}) \] ### Final Output Thus, the corresponding output signal is: \[ V_{out} = 300 \cos(15t + \frac{4\pi}{3}) \]
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AAKASH INSTITUTE-SEMICONDUCTOR ELECTRONICS (MATERIAL, DEVICES AND SIMPLE CIRUITS )-Assignment section -C (Previous years type question)
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