A transistor has a current amplification factor of 60. In a CE amplifier, input resistance is `1 kOmega` and output voltage is `0.01 V`. The transconductance is (in SI units)

Options

A. `10^(-5)`
B. `6 xx 10^(-2)`
C. `6 xx 10^(4)`
D. 10

Answer

To find the transconductance of the transistor in a common emitter (CE) amplifier, we can use the relationship between the current amplification factor (β), the input resistance (R_I), and the transconductance (g_m). Here’s how to solve the problem step by step:

### Step-by-Step Solution:

1. **Identify the given values:**
- Current amplification factor (β) = 60
- Input resistance (R_I) = 1 kΩ = 1000 Ω
- Output voltage (V_out) = 0.01 V (though this value is not needed for calculating transconductance in this case)

2. **Understand the formula for transconductance:**
- Transconductance (g_m) is defined as:
\[ g_m = \frac{\beta}{R_I} \]
- Here, β is the current gain and R_I is the input resistance.

3. **Substitute the values into the formula:**
- Plugging in the values we have:
\[ g_m = \frac{60}{1000} \]

4. **Calculate the transconductance:**
- Performing the division:
\[ g_m = 0.06 \, \text{S} \quad (\text{Siemens is the unit of transconductance}) \]

5. **Convert to SI units:**
- In scientific notation, this can be expressed as:
\[ g_m = 6 \times 10^{-2} \, \text{S} \]

### Final Answer:
The transconductance is \( 6 \times 10^{-2} \, \text{S} \).