In a common emitter configuration base current is `40 mu A` and current gian is 100. The collector current will be

Options

A. `4 mA`
B. `4 mu A`
C. `1 mA`
D. `1 mu A`

Answer

To find the collector current (IC) in a common emitter configuration, we can use the relationship between the base current (IB), the current gain (β), and the collector current (IC). The formula is given by:

\[ IC = β \times IB \]

**Step 1: Identify the given values.**
- Base current (IB) = 40 µA = 40 × 10^-6 A
- Current gain (β) = 100

**Step 2: Substitute the values into the formula.**
Using the formula for collector current:
\[ IC = β \times IB \]
\[ IC = 100 \times (40 \times 10^{-6}) \]

**Step 3: Perform the multiplication.**
\[ IC = 100 \times 40 \times 10^{-6} \]
\[ IC = 4000 \times 10^{-6} \]
\[ IC = 4 \times 10^{-3} \text{ A} \]

**Step 4: Convert to milliampere.**
Since 1 A = 1000 mA:
\[ IC = 4 \text{ mA} \]

Thus, the collector current (IC) is **4 mA**.