`x/2 + 2/x` has local minima at

f(x)= {{:(x, 0 (A) g(x) has no local maxima (B) g(x) has no local minima (C) g(x) has local maxima at x=1+ln2 and local minima at x=e (D) g(x) has local minima at x=1+2ln2 and local maxima at x=e

Let f(x)={(sin(pi x))/(2),0 =1f(x) has local maxima at x=1f(x) has local minima at x=1f(x) does not have any local extrema at x=1f(x) has a global minima at x=1

f(x) is cubic polynomial with f(x)=18 and f(1)=-1 . Also f(x) has local maxima at x=-1 and f^(prime)(x) has local minima at x=0 , then (A) the distance between (-1,2)a n d(af(a)), where x=a is the point of local minima is 2sqrt(5) (B) f(x) is increasing for x in [1,2sqrt(5]) (C) f(x) has local minima at x=1 (D)the value of f(0)=15

If f(x)=int_0^x(sint)/t dt ,x >0, then (a) f(x) has a local maxima at x=npi(n=2k ,k in I^+) (b) f(x) has a local minima at x=npi(n=2k ,k in I^+) (c) f(x) has neither maxima nor minima at x=npi(n in I^+) (d) (f)x has local maxima at x=npi(n=2k -1, k in I^+)

If f(x)=int_0^x(sint)/t dt ,x >0, then (a) f(x) has a local maxima at x=npi(n=2k ,k in I^+) (b) f(x) has a local minima at x=npi(n=2k ,k in I^+) (c) f(x) has neither maxima nor minima at x=npi(n in I^+) (d) (f)x has local maxima at x=npi(n=2k +1, k in I^+)

Given f(x)={(x^(2)-4|x|+a ,if, x le 2),(6-x, if, x gt 2):} ,then number of positive integral values of a for which f(x) has local minima at x=2 .

Let f(x)={(|x-2|+a^2-9a-9 ,ifx lt 2, 2x-3 ,ifx ge 2:} Then find value of 'a' for which f(x) has local minima at x= 2

f(x) is cubic polynomial with f(x)=18a n df(1)=-1 . Also f(x) has local maxima at x=-1a n df^(prime)(x) has local minima at x=0 , then (A) the distance between (-1,2)a n d(af(a)), where x=a is the point of local minima is 2sqrt(5) (B) f(x) is increasing for x in [1,2sqrt(5]) (C) f(x) has local minima at x=1 (D)the value of f(0)=15