A=[[1,-1,1],[2,1,-3],[1,1,1]]" and "10B=[[4,2,2],[-5,0,alpha],[1,-2,3]]

Let A = [(1,-1,1),(2,1,-3),(1,1,1)] and (10)B = [(4,2,2),(-5,0,alpha),(1,-2,3)] If B is the inverse of A , then alpha is :

Let A=[(1,-1,1),(2,1,-3),(1,1,1)] and B=[(4,2,2),(-5,0,alpha),(1,-2,3)] If B is the inverse of matrix A , then alpha= (A) 2 (B) -2 (C) 5 (D) -5

Let A=((1,-1,1),(2,1,-3),(1,1,1)) and (10) B=((4,2,2),(-5,0,alpha),(1,-2,3)) . If B is the inverse of matrix A, then alpha is

If inverse of A=[{:(1,-1,1),(2,1,-3),(1,1,1):}] is (1)/(10)[{:(4,2,2),(-5,0,alpha),(1,-2,3):}] then alpha =…..

If A=[[1,0,5],[2,-1,3],[4,1,0]] and B=[[3,2,1],[0,2,1],[3,2,5]] .Show that (a) ( A + B )' = A' + B' (b) (2A)'=2A'

If A = [[1,2,-3],[5,0,2],[1,-1,1]], B = [[3,-1,2],[4,2,5],[2,0,3]] and C = [[4,1,2],[0,3,2],[1,-2,3]] , then compute (A+B) and (B-C) . Also, verify that A + (B-C) = (A + B) - C .

If A=[[1,0,-2],[3,-1,0],[-2,1,1]],B=[[0,5,-4],[-2,1,3],[-1,0,2]] and C=[[1,5,2],[-1,1,0],[0,-1,1]] verify that A(B-C)=(AB-AC)