Consider a complex number `z =(2w+1)/(iw+1)` where `w=x+iy` if `I_m(z)=-2` then the locus of `omega` is a straight line. Find the x-intercept of the line

Consider a complex number w=(z-1)/(2z+1) where z=x+iy, where x,y in R . If the complex number w is purely imaginary then locus of z is

If z=x+iy, then the equation |(2z-i)/(z+1)|=k will be a straight line,where -

Consider the two complex numbers z and w, such that w=(z-1)/(z+2)=a+ib, " where " a,b in R " and " i=sqrt(-1). If z=CiStheta , which of the following does hold good?

Consider the two complex numbers z and w, such that w=(z-1)/(z+2)=a+ib, " where " a,b in R " and " i=sqrt(-1). If z=CiStheta , which of the following does hold good?

If z is a complex number satisfying the equation |z-(1+i)|^2=2 and omega=2/z , then the locus traced by 'omega' in the complex plane is

If z is a complex number satisfying the equation |z-(1+i)|^2=2 and omega=2/z , then the locus traced by 'omega' in the complex plane is

If w=z/[z-(1/3)i] and |w|=1, then find the locus of z

If w=z/[z-(1/3)i] and |w|=1, then find the locus of z

If w=z/[z-1/(3i)] and |w|=1, then find the locus of z