[" In the binomial expansion of "(a-b)^(n);n>=5," the sum of "5^(" th ")" and "6^(" th ")],[" terms is zero,then a/b equals "]

In the binomial expansion of (a - b)^(n) , n ge 5 , the sum of the 5^(th) and 6^(th) terms is zero. Then, a//b equals

In the binomial expansion of (a - b)^(n) , n gt= 5 , the sum of 5^(th) and 6^(th) term a/b equals

Let nge5 and bne0 . In the binomial expansion of (a-b)^(n) , the sum of the 5^(th) and 6^(th) terms is zero. Then a//b equals

In the binomial expansion of (a-b)^(n) , n ge 5 , the sum of 5th and 6th terms is zero, then (a)/(b) equals

In the binomial expansion of (a-b)^(n),n>=5 the sum of the 5 th and 6 th term is zero.Then a/b equals (n-5)/6 b.(n-4)/5 c.n/(n-4)d*6/(n-5)

In the binomial expansion of (a-b)^(n),nge5 , the sum of the 5th and 6th terms is zero. Then a/b equals:

In the binomial expansion of (a-b)^n , ngeq5, the sum of 5th and 6th terms is zero, then a/b equals (1) 5/(n-4) (2) 6/(n-5) (3) (n-5)/6 (4) (n-4)/5