The solution of the equation `[[1,0 ,1],[-1,1 ,0],[0 ,-1,1]][[x],[ y] ,[z]]=[[1],[ 1],[ 2]]` is

The solutiion of (x,y,z) the equation [(-1,0,1),(-1,1,0),(0,-1,1)][(x),(y),(z)]=[(1),(1),(2)] is (x,y,z)

The solutiion of (x,y,z) the equation [(-1,0,1),(-1,1,0),(0,-1,1)][(x),(y),(z)]=[(1),(1),(2)] is (x,y,z)

If [[1,0,0],[0,1,0],[0,0,1]][[x],[y],[z]]=[[1],[-1],[0]] then value of (x+y+z)is

If [[1,0,0],[0,y,0],[0,0,1]][[x],[-1],[z]]=[[1],[2],[1]], then the value of x+y+z is

If [[1 1 1],[0 1 1],[0 0 1]] [[x],[y],[z]] = [[6],[3],[2]] ,then 2x+y-z=?

The equation [1 x y][(1,3,1),(0,2,-1),(0,2,-1)] [(1),(x),(y)]=[0] has

The equation [(1, x, y)][(1,3,1),(0,2,-1),(0,2,-1)] [(1),(x),(y)]=[0] has

The equation [[1, 2 ,2 ],[1 ,3, 4],[ 2, 4,k]][[x ,y, z]] =[[0,0, 0]] has a solution for (x ,y ,z) besides (0,0,0)dot Then the value of k is _______.

If x ,\ y ,\ z are non-zero real numbers, then the inverse of the matrix A=[[x,0, 0],[ 0,y,0],[ 0, 0,z]] , is (a) [[x^(-1),0 ,0 ],[0,y^(-1),0],[ 0, 0,z^(-1)]] (b) x y z[[x^(-1),0 ,0],[ 0,y^(-1),0],[ 0, 0,z^(-1)]] (c) 1/(x y z)[[x,0, 0],[ 0,y,0],[ 0, 0,z]] (d) 1/(x y z)[[1, 0, 0],[ 0 ,1, 0],[ 0, 0, 1]]

The equation [[1, 2 ,2 ],[1 ,3, 4],[ 2, 4,k]][(x) ,(y), (z)] =[(0),(0), (0)] has a solution for (x ,y ,z) besides (0,0,0)dot Then the value of k is _______.