If `sinalpha+cosbeta=2,(0^(@) le beta lt alpha90^(@))`, then `sin((2alpha+beta)/(3))=?`

If sinalpha+cosbeta=2(o^(@)lebetaltalphale90^(@)) , then sin((2alpha+beta)/(3))=

sin alpha=(12)/(13) (0 lt alpha lt (pi)/(2)r) cos beta=-(3)/(5)(pi lt beta lt (3 pi)/(2)) then sin (alpha+beta) is

If sin alpha + sin beta=a and cos alpha+cosbeta=b then tan((alpha-beta)/2) is equal to

Let cos alpha + cos beta =2 and sinalpha + sinbeta =0 , where 0 le alpha le 90^(@), 0 le beta le 90^(@) . What is the value of cos2alpha - cos 2beta ?

If sinalpha=1/2 and cosbeta=1/2 , then the value of (alpha+beta) is

If sinalpha=1/2 and cosbeta=1/2 , then the value of (alpha+beta) is

(sinalpha cos beta+cos alpha sin beta)^2+(cos alpha cos beta-sin alpha sin beta)^2=1

If sinalpha=(1)/(3) and cosbeta=(4)/(5), " then find " sin(alpha+beta) .

cos (alpha+beta)=(3)/(5) and sin (alpha-beta)=(3)/(5) and 0 lt alpha, beta lt (pi)/(2) then sin 2 alpha=