if `log_2(log_3(log_4x))=0` and `log_3(log_4(log_2y))=0`and `log_3(log_2(log_3z))=0` then find the sum of `x, y` and `z` is

If log_2(log_3(log_4(x)))=0, log_3(log_4(log_2(y)))=0 and log_4(log_2(log_3(z)))=0 then the sum of x,y,z is

If log_(2)(log_(3)(log_(4)(x)))=0 and log_(3)(log_(4)(log_(2)(y)))=0 and log_(4)(log_(2)(log_(2)(z)))=0 then the sum of x,y and z is _(-)

If log_(2)(log_(4)(x))) = 0, log_(3)(log_(4)(log_(2)(y))) = 0 and log_(4)(log_(2)(log_(3)(z))) = 0 then the sum of x,y and z is-

If log_(2)(log_(4)(x))) = 0, log_(3)(log_(4)(log_(2)(y))) = 0 and log_(4)(log_(2)(log_(3)(z))) = 0 then the sum of x,y and z is-

If log_(2)(log_(4)(x))) = 0, log_(3)(log_(4)(log_(2)(y))) = 0 and log_(4)(log_(2)(log_(3)(z))) = 0 then the sum of x,y and z is-

If log_2 (log_3 (log_4 x))= 0, log_4 (log_3 (log_2 y))= 0 and log_3(log_4 (log_2z ))= 0, then the correct option is

Solve : log_4(log_3(log_2x))=0

If log_2 (log_2 (log_3 x)) = log_2 (log_3 (log_2 y))=0 , then the value of (x+y) is

If log_(2)(log_(2)(log_(3)x))=log_(2)(log_(3)(log_(2)y))=0 then the value of (x+y) is

log_(2)log_(3)log_(4)(x-1)>0