`(64)^(1/3)[(64)^(1/3)-(64)^(2/3)]=?`

64^(2/3)xx64^(1/3)xx64^((-5)/3)

(64/512)^(1/3)

x-64x^(3)

Simplify sqrt(25)/(64)^(1/3)+(256/625)^(-1/4)+1/(64/125)^(2/3)

Find the mean mu and variance sigma^2 for the following probability distribution : X: 0 1 2 3 P(X): 1/(64) (18)/(64) (18)/(64) (27)/(64)

{(1/3)^(-3)-(1/2)^(-3)}-:(1/4)^(-3) = (19)/(64) (b) (64)/(19) (27)/(16) (d) (-19)/(64)

{(1/3)^(-3)-(1/2)^(-3)}-:(1/4)^(-3) = (a) (19)/(64) (b) (64)/(19) (c) (27)/(16) (d) (-19)/(64)