In the adjoining figure BC||DE. Area of ` triangle= 25 cm^(2)` .area of trapezium `BCED= 24cm^(2)` , DE= 14 cm, calculate length of BC.

In the given figure, BC is parallel to DE. Area of triangle ABC = 25 cm^2 , Area of trapezium BCED = 24 cm^2 and DE = 14 cm . Calculate the length of BC. Also, find the area of triangle BCD.

In the adjoining figure, DE || BC . Prove that area (Delta ACD) = " area " (Delta ABE)

In the adjoining figure, DE || BC . Prove that area (DeltaACD) = " area " (DeltaABE)

In the adjoining figure, DE////BC and D divides AB in the ratio 2 : 3. Find DE, if BC = 7.5 cm.

In the adjacent figure DE is parallel to BC and ratio of areas of DeltaADE and trapezium BDEC is 4 : 5. What is the value of DE : BC?

Let ABC ~ triangle DEF and their areas be 81 cm^(2) and 144 cm^(2) . If EF = 24 cm, then length of side BC is ……………………. Cm

In the adjoining figure, DE||BC and AD=1 cm,BD=2 cm.What is the ratio of the area of triangleABC to the area of triangleADE ?

In the given figure, AB and DE are perpendiculars to BC. If AB = 9 cm, DE = 3 cm and AC = 24 cm, calculate AD.

In the given figure ABCD s a trapezium of area 24.5cm^(2) . If AD||BC, /_DAB=90^(@),AD=10cm,BC=4cm and ABE is quadrant of a circle then find the area of the shaded region.