The equation of straight line which is equidistant from the points `A(2,-2), B(6,1)` and `C(-3, 4)` can be

The equation of the line which is equidistant from the lines 2x+y+4=0,3x+6y-5=0 is

The equation of the locus of the points equidistant from the points A(-2,3) & B(6,-5) is

The equation of straight line equally inclined to the axes and equidistant from the point (1,-2) and (3,4) is:

Find the point on the straight line 3x+y+4=0 which is equidistant from the points (-5,6) and (3,2).

The point on the line 4x-y-2=0 which is equidistant from the points (-5,6) and (3,2) is

The point on the line 4x-y-2=0 which is equidistant from the points (-5,6) and (3,2) is

The equation of straight line equally inclined to the axes and equidistant from the point (1,-2) and (3,-4) is

The equation of straight line equally inclined to the axes and equidistant from the point (1, -2) and (3,4) is: