The vertex A of triangle ABC is at origin. The equation of median through B and C are `15x -4y =240 and 15x-52y+240=0` respectively. Then

In a triangle ABC, if A is (1, 2) and the equations of the medians through B and c are x+ y= 5 and x= 4 respectively then B must be:

in a triangle ABC, if A is (1,2) and the equations of the medians through B and c are x+y=5 and x=4 respectively then B must be:

The vertex C of a triangle ABC is (4,-1) . The equation of altitude AD and Median AE are 2x-3y+12=0 and 2x+3y=0 respectively then slope of side AB is :

The vertex A of DeltaABC is (3,-1). The equation of median BE and angle bisector CF are x-4y+10=0 and 6x+10y-59=0, respectively. Equation of AC is

The vertex A of DeltaABC is (3,-1). The equation of median BE and angle bisector CF are x-4y+10=0 and 6x+10y-59=0, respectively. Equation of AC is

The vertex A of DeltaABC is (3,-1). The equation of median BE and angle bisector CF are x-4y+10=0 and 6x+10y-59=0, respectively. Equation of AC is

The vertex A of DeltaABC is (3,-1). The equation of median BE and angle bisector CF are x-4y+10=0 and 6x+10y-59=0, respectively. Equation of AC is

In a triangle ABC, coordinates of A are (1,2) and the equations of the medians through B and C are x+y=5 and x=4 respectively. Find the coordinates of B and C.

In a triangle ABC, co-ordinates of A are (1,2) and the equations to the medians through B and C are x+y=5 and x=4 respectively.Then the co-ordinates of B and C will be