[" The minimum value of the function "y=(a^(2))/(x)+(b^(2))/(a-x),a>0,b>0" in "],[(0,a)" is : "]

The minmumu value of the fucntion f(x)=a^2/x+b^2/(a-x),a gt 0, b gt 0 , in (0,a) is

The minmumu value of the fucntion f(x)=a^2/x+b^2/(a-x),a gt 0, b gt 0 , in (0,a) is

If a,bgt0 then the minimum value of y=(b^(2))/(a-x)+(a^(2))/(x),0ltxlta is

If a,b>0 then the minimum value of y=(b^(2))/(a-x)+(a^(2))/(x),0

The least value of the function f(x) = ax + (b)/(x) (x gt 0, a gt 0, b gt 0)

The maximum value of the function f(x)=((1+x)^(0. 6))/(1+x^(0. 6)) in the interval [0,1] is 2^(0. 4) (b) 2^(-0. 4) 1 (d) 2^(0. 6)

The maximum value of the function f(x)=((1+x)^(0. 6))/(1+x^(0. 6)) in the interval [0,1] is 2^(0. 4) (b) 2^(-0. 4) 1 (d) 2^(0. 6)

If a,b>0, then minimum value of y=(b^(2))/(a-x)+(a^(2))/(x)in(0,a) is (a+b)/(a) (b) (ab)/(a+b)(1)/(a)+(1)/(b) (d) ((a+b)^(2))/(a)

For 0

The minimum value of a sec x+b cos ecx,0