Home
Class 11
PHYSICS
[" C.On Deriving a physical relation "],...

[" C.On Deriving a physical relation "],[" Show dimensionally that the time period of a simple "],[" pendulum is given by "],[qquad t=2 pi sqrt((l)/(g))" ."],[" Where "l" is length of the pendulum and "g" is acceleration "]

Promotional Banner

Similar Questions

Explore conceptually related problems

Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally currect

Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally currect

Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally correct

Show that the expression of the time period T of a simple pendulum of length l given by T = 2pi sqrt((l)/(g)) is dimensionally correct

Time period T of a simple pendulum of length l is given by T = 2pisqrt((l)/(g)) . If the length is increased by 2% then an approximate change in the time period is

If the time period of a simple pendulum is T = 2pi sqrt(l//g) , then the fractional error in acceleration due to gravity is

If the time period of a simple pendulum is T = 2pi sqrt(l//g) , then the fractional error in acceleration due to gravity is

Derive an expression for the time period (T)of a simple pendulum which may depend upon the mass (m) of the bob , length (l) of the pendulum and acceleration due to gravity(g).

Time period T of a simple pendulum of length l is given by T=2pisqrt((l)/(g)) . If the length is increased by 2% then an approximate change in the time period is