A compound on analysis gave the follwing result C=54.54%,H=9.09% and vapour density of compound = 88.Determine the molecular formula of the compound :-

A compound on analysis gave the following results C = 54.54% , H=9.09% and rest is oxygen and vapour density of the compound = 88. Determine the molecular formula of the compound.

An organic fruit smelling compound on analysis has the following composition by mass: C = 54.54%, H = 9.09%, O = 36.36%. Find out the molecular formula of the compound. The vapour density of the compound was found to be 44

An organic compound containing carbon, hydrogen and oxygen gave the following percentage composition : C = 40.68%, H = 5.08% The vapour density of the compound is 59. Calculate the molecular formula of the compound.

A compound on analysis gave the following percentage composition: C - 54.54%, H = 9.09%, O = 36.36% . The vapour density of compound was found to be 44. Find out the molecular formula of compound.

A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09% 0 = 36.36. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound.

A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09% 0 = 36.36. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound.

A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09% O = 36.36. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound.

A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09% 0 = 36.36. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound.

A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09% 0 = 36.36. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound.