" So "cos6x=32cos^(6)x-48cos^(9)x+18cos^(2)x-1

cos6x=32cos^(6)x-48cos^(4)x+18cos^(2)x-1

cos6x=32cos^(6)x-48cos^(4)x-18cos^(2)x-1

Prove that cos6x=32cos^(6)x-48cos^(4)x+18cos^(2)x-1

Prove that: quad cos6x=32cos^(6)x-48cos^(4)x+18cos^(2)x-1

Prove that: cos6x=32cos^6x-48cos^4x+18cos^2x-1

Prove that cos6A=32cos^(6)A-48cos^(4)A+18cos^(2)A-1

Prove that: cos 6x=32 cos^(6)x-48 cos^(4)x+18 cos^(4)x+18 cos^(2)x-1 .

6cos^(3)x+cos^(2)x-1=0

Prove that cos6x=32cos^6x-48cos^4x+18cos^2x-1

What is the value of ((32cos^(6)x-48cos^(4)x+18cos^(2)x-1))/(4sinxcosxsin(60-x)cos(60-x)sin(60+x)cos(60+x)) ?