" If "f(theta)=|[cos theta,1,0],[1,2cos theta,1],[0,1,2cos theta]|" then range of "f(theta)" is "

If f(theta)=det[[cos theta,1,01,2cos theta,10,1,2cos theta]] then range

If f(theta)=[(cos theta, -sin theta,0),(sin theta, cos theta, 0),(0,0,1)] then {f(theta)^(-1)} is equal to

If F(theta)=[[cos theta,-sin theta, 0],[sin theta, cos theta, 0],[0,0,1]] , then show that F(theta) F (phi)= F(theta + phi) .

If f(theta)=|[cos^(2)theta,cos theta sin theta,-sin theta],[cos theta sin theta,sin^(2)theta,cos theta],[sin theta,-cos theta,0]| , then f((pi)/(12))

If f(theta)=(1-sin2 theta+cos2 theta)/(2cos2 theta), then value of 8f(11^(0))*f(34^(0))^(0) is

consider f_(n)(theta)=(2cos theta-1)(2cos2 theta-1)(2cos(2^(2)theta)-1)....(2cos(2^(n)theta)-1) the value of f_(n)(theta) is equal to

If A = [( 1, cos theta , 1),( - cos theta ,1,cos theta ),( -1 , - cos theta ,1)] where 0 le theta le 2 pi then …..

If A = [( 1, cos theta , 1),( - cos theta ,1,cos theta ),( -1 , - cos theta ,1)] where 0 le theta le 2 pi then …..

Consider f(theta)=|[sin theta,cos theta,sin theta],[cos theta,sin theta,cos theta],[cos theta,sin theta,sin theta]| then A) f(theta)=0 has exactly 2 real solutions in [0,pi] B) f(theta)=0 has exactly 3 real solutions in [0,pi] C) Range of function (f(theta))/(1-sin2 theta) is [-sqrt(2),sqrt(2)] D) Range of function (f(theta))/(sin2 theta-1) is [-3,3]