`O(g) +2e^(-1) rarr O^(-2) (g) -E = +744.7` The reaction for the positive value of `e` is

O(g) + 2e^(-) to O^(2-)(g) , DeltaH_(eg) = 744.7 kJ/mole . The positive value of DeltaH_(eg) is due to :

O(g) + 2e^(-) to O^(2-)(g) , DeltaH_(eg) = 744.7 kJ/mole . The positive value of DeltaH_(eg) is due to :

Given that O(g) + e^(-) rarr O^(-)(g) Delta H = - 142 kJ mol^(-1) O(g) + 2e^(-) rarr O^(2-)(g) DeltaH =+712kJmol^(-1) The heat change for the reaction O^(-)(g) + e^(-) rarr O^(2-)(g) is :

If S(g)+e^(-) rarr S^(1-)(g), Delta H = -207.6 KJ S(g) + 2e^(-) rarr S^(2-)(g), Delta H = +335.2 KJ . The enthalpy for the reaction S^(1-)(g)+e^(-) rarr S^(2-)(g) :

The electrode potential of some half cell reactions are : Cl_(2) + 2e^(-) rarr 2 Cl^(-)(aq), E^(@) = + 1.36 V O_(2)+2H^(+)(aq) + 2e^(-) rarr H_(2)O_(2) (aq) , E^(@) = + 0.65 V F_(2)+2e^(-) rarr 2F^(-)(aq), E^(@) = + 2.87 V H_(2)O+ 2e^(-) rarr H_(2)(g) + 2OH^(-) (aq), E^(@) = - 0.83 V The strongest oxidising agent is :

From the following E^(o) value of helf cells: (i) A+e^(-)rarr A ^(-) , E^(o) = -0.824 V (ii) B^(-)+e^(-)rarr B ^(2-) , E^(o) = +1.25V (iii) C^(-)+2e^(-)rarr C ^(3-) , E^(o) = -1.25V (iv) D^(-)+2e^(-)rarr D ^(2-) , E^(o) = +0.68V What combination of two half cells would result is a cell with the largest cell potential?

Given that O(g)+e^(-)rarrO^(-)(g) , DeltaH=34Kcal mol^(-1) O(g)+2e^(-)(g)rarrO^(2-)(g) , DeltaH=168Kcal mol^(-1) The enthalply change for the reaction O^(-)(g)+e^(-)rarrO^(2-)(g) is