Find displacement of a particle in 1-D if its velocity is `v=(2t-5) m//s` , from `t=0` to `t=4` sec.

The displacement of a particle is given by y (t) =2t ^(2) +5m. Hence its velocity at the end of 6 sec. will be ...... m/s.

If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the velocity of particle at t=2 is

5.The displacement s of a particle at a time t is given by s=2t-5t+4t-3, find (i) the time when the acceleration is 14 ft/sec (ii) the velocity and the displacement at that time.

The acceleration of particle varies with time as shown. (a) Find an expression for velocity in terms of t. (b) Calculate the displacement of the particle in the interval from t = 2 s to t = 4 s. Assume that v = 0 at t = 0.

The acceleration of particle varies with time as shown. (a) Find an expression for velocity in terms of t. (b) Calculate the displacement of the particle in the interval from t = 2 s to t = 4 s. Assume that v = 0 at t = 0.

The displacement of a particle at time t is given by s= 2 t^3 - 5 t^2 + 4t -3. Find the time when the acceleration is 14 ft/ sec^2 , find the velocity and the displacement at that time.

The displacement of a particle at time t is given by s= 2t^(3) -5t^(2)+ 4t-3 . Find the velocity when t = 2 sec.

The displacement s of a particle at time t is is given by s=2 t^3 - 4 t^2 -5t. Then find the velocity at t=2 sec

The angular displacement of a particle is given by theta=t^(3)+ t^(2)+ t+1 then, its angular velocity at t = 2sec is ……….. rad s^(-1)