Find the equation of circle passing through the origin and cutting the circles
`x^(2) + y^(2) -4x + 6y + 10 =0` and `x^(2) + y^(2) + 12y + 6 =0` orthogonally.

The equation of the circle passing through the origin delta cutting the circles x^(2)+y^(2)-4x+6y+10=0 and x^(2)+y^(2)+12y+6=0 at right angles is -

If the circles x^(2) + y^(2) - 6x - 8y + 12 = 0 , x^(2) + y^(2) - 4x + 6y + k = 0 cut orthogonally, then k =

The equation of the circle passing through (0,0) and cutting orthogonally the circles x^(2) + y^(2) + 6x - 15 = 0 , x^(2) + y^(2) - 8y + 10 = 0 is

Find the equation of the circle passing through (-2,14) and concentric with the circle x^(2)+y^(2)-6x-4y-12=0

Find the equation of the circle passing through (-2,14) and concentric with the circle x^(2)+y^(2)-6x-4y-12=0

Find the equation of the circle passing through (-2,14) and concentric with the circle x^(2)+y^(2)-6x-4y-12=0

Find the equation of the circle passing through the points of intersection of the circles x^(2)+y^(2)-8x-6y-21=0 x^(2)+y^(2)-2x-15=0and(1,2)

Find the equation of the circle which passes through the origin and intersects the circles below, orthogonally. x^2 + y^2 - 4x + 6y + 10 = 0 . x^2 + y^2 + 12y + 6 = 0 .

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^(2)+y^(2)-6x+8=0 and x^(2)+y^(2)-2x-2y-7=0 is