A rectangular container moves with an acceleration a along the positive direction as shown in figure. The pressure at the `A` in excess of the atmospheric pressure `p_(0)` is (take `rho` as the density of liquid)

A metal sphere connected by a string is dipped in a liquid of density rho as shown in figure. The pressure at the bottom of the vessel will be, (p_(0) =atmospheric pressure )

A metal sphere connected by a string is dipped in a liquid of density rho as shown in figure. The pressure at the bottom of the vessel will be, (p_(0) =atmospheric pressure )

Assertion : In the given figure shown, p_(1)=p_(2) . Reason : Pressure at 1 is less than the atmospheric pressure.

A liquid kept in a container has a horizontal acceleration 'a' as shown in figure. Using the pressure equation along the path ABC find the angle theta .

A liquid kept in a container has a horizontal acceleration 'a' as shown in figure. Using the pressure equation along the path ABC find the angle theta .

A L Shaped tube containing liquid of density pis accelerated horizontally with acceleration as shown in the figure. The end of tube B is closed while end A is open. If the atmospheric pressure is Po . Then the pressure at B is :

A cylidrical vesel containing a liquid is closed by a smooth piston of mass m as shown in the figure. The area of cross section of the piston is A. If the atmospheric pressure is P_0 , find the pressure of the liquid just below the piston. ,

A cylidrical vesel containing a liquid is closed by a smooth piston of mass m as shown in the figure. The area of cross section of the piston is A. If the atmospheric pressure is P_0 , find the pressure of the liquid just below the piston. ,