If `tanA-tanB=x` and `cotB-cotA=y` , then `cot(A-B)` . is equal to (i) `1/y-1/x` (ii) `1/x-1/y` (iii)`1/y+1/x` (iv) `1/(x+y)`

If tanA-tanB=x a n dcotB-cotA=y , prove that cot(A-B)=1/x+1/y

If tanA-tan B=x and cot B- cot A=y . Prove that cot(A-B)=1/x + 1/y

If tan A -tan B = x and cot B - cot A = y, prove that cot(A-B)=1/x+1/y

tan A-tan B=x and cot A-cot B=y prove that cot(A-B)=(1)/(x)-(1)/(y)

tan A-tan B=x and cot A-cot B=y prove that cot(A-B)=(1)/(x)-(1)/(y)

If tan A - tan B = x and cot B - cot A =y , then what is cot ( A -B) equal to ?.............. A) 1/x +ya B) (1)/(xy) C) (1)/(x) -(1)/(y) D) (1)/(x) +1/y

If tan A-tan B=x,cot B-cot A=y prove that cot(A-B)=(1)/(x)+(1)/(y)

If tan^(-1)x + tan^(-1)y=4pi//5 , then cot^(-1)x + cot^(-1)y is equal to