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For the reaction NOBr (g)iffNO(g)+(1)/(2...

For the reaction `NOBr (g)iffNO(g)+(1)/(2)Br_(2)(g)`
`K_(P)=0.15 atm` at `90^(@)C`. If `NOBr, NO` and `Br_(2)` are mixed at this temperature having partial pressures `0.5 atm`, and `0.2 atm` respectively, will `Br_(2)` be consumed or formed?

Text Solution

Verified by Experts

`Q_(P)=([P_(Br_(2))]^(1//2)[P_(NO)])/([P_(NOBr]])=([0.2]^(1//2)[0.4])/([0.50])=0.36`
`K_(P)=0.15`
`therefore Q_(P)gtK_(P)`
Hence, reaction will shift in backward direction `therefore Br_(2)` will be consumed
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