`0.96 g` of `HI` were heated to attain equilibrium `2HIhArrH_(2)+I_(2)`. The reaction mixture on titration requires `15.7mL` of `N//10` hypo solution. Calculate degree of dissociation of `HI`.

Answer

`20.9%`

Explanation

meq of `l_(2)=(W_(l_2))/(127)xx1000=1.57`
`W_(l_(2))=(127xx1.57)/(1000)` `n_(l_(2))=(1.57)/(2000)``2HI(g)harrH_(2)(g)+l_(2)(g)`
`a-aalpha , (aalpha)/(2) , (aalpha)/(2) , (0.96)/(256)xxalpha=(1.57)/(2000)`
`alpha=0.209`