In a vessel, two equilibrium are simultanceously established at the same temperature as follows:
`N_(2)(g)+3H_(2)(g)hArr2 NH_(3)(g)`.... (1)
`N_(2)g)+2H_(2)(g)hARrN_(2)H_(4)(g)` ....(2)
Initially the vessel contains `N_(2) "and" H_(2)` in the molar ratio of `9:13`. The equilibrium pressure is `7P_(0)`, in wich pressure due to ammonia is `P_(o)` and due to hydrogen is `2P_(0)`. Find the values of equilibrium constats `(K_(p)'S)` for both the reactions

Answer

`K_(p1)=(1)/(2OP_(0)^(2)),K_(p3)=(3)/(2OP_(0)^(2)`