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The active mass of 64 g of HI in a 2-L f...

The active mass of `64 g` of `HI` in a `2-L` flask would be

A

(A) `22:3:7`

B

(B) `0.5:3:7`

C

(C) `1:3:1`

D

(D) `1:3:0.5`

Text Solution

Verified by Experts

The correct Answer is:
D
Molar conc.`=(22)/(44)=(1)/(2)`
Moles of `H_(2)=(3)/(2) rArr "Moles of" N_(2)=(7)/(28)=(1)/(4)`
Ratio of active massess`=1//2:3//2:1//4 "or"1:3:0.5`.
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