Active mass of a `6%` solution of a compound is `2` then calculate molar mass of compound.

Options

A. (A) `15`
B. (B) `30`
C. (C) `60`
D. (D) `120`

Answer

To solve the problem of calculating the molar mass of a compound from the given information about a 6% solution, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Definition of a 6% Solution**:
A 6% solution means that there are 6 grams of solute in every 100 mL of solution.

2. **Identify the Given Data**:
- Weight of solute (W) = 6 grams
- Volume of solution (V) = 100 mL
- Active mass (molar concentration, C) = 2 M (molar)

3. **Convert Volume to Liters**:
Since molarity is expressed in moles per liter, we need to convert the volume from mL to liters.
\[ V = 100 \, \text{mL} = \frac{100}{1000} \, \text{L} = 0.1 \, \text{L} \]

4. **Use the Molarity Formula**:
The formula for molarity (C) is given by:
\[ C = \frac{W}{M \times V} \]
where:
- \( C \) = molarity (2 M)
- \( W \) = weight of solute (6 g)
- \( M \) = molar mass of solute (unknown)
- \( V \) = volume of solution in liters (0.1 L)

5. **Rearrange the Formula to Solve for Molar Mass (M)**:
Rearranging the formula gives:
\[ M = \frac{W}{C \times V} \]

6. **Substitute the Known Values**:
Now substitute the known values into the equation:
\[ M = \frac{6 \, \text{g}}{2 \, \text{mol/L} \times 0.1 \, \text{L}} \]

7. **Calculate the Molar Mass**:
\[ M = \frac{6}{0.2} = 30 \, \text{g/mol} \]

### Final Answer:
The molar mass of the compound is **30 g/mol**.

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