In a reversible reaction `Aunderset(K_2)overset(K_1)hArrB` the initial concentration of A and B are a and b in moles per litre and the equilibrium concentrations are (a-x) and (b+x) respectively, Express x in terms of `K_1, K_2, a and b`.

Options

A. (A) `(K_(1)a-K_(2)b)/(K_(1)+K_(2))`
B. (B) `(K_(1)a-K_(2)b)/(K_(1)-(K_(2))`
C. (C) `(K_(1)a-K_(2)b)/(K_(1)K_(2))`
D. (D) `(K_(1)a-K_(2)b)/(K_(1)+K_(2))`

Answer

A

Explanation

`Aoverset(K_(1))underset(K_(2))(hArr)B K_(2)=(K_(1))/(K_(2))=(b-x)/(a-x)`
`a-x b+x x=(K_(1)a-K_(2)b)/(K_(1)+K_(2))` Therefore, `(A)` option is coreect.