`K_(c) = 9` for the reaction, `A + B hArrC + D`. If A and B are taken in equal amounts, then amount of C in equilibrium is:

Options

A. (A) `1`
B. (B) `0.25`
C. (C) `0.75`
D. (D) None of these

Answer

C

Explanation

`A+BhArrO+D`
`{:(Initial,1,1,0,0),("at equili",(1-x),(1-x),x,x):}`
`therefore K_(c)=([C][D])/([A][B])=9`
`therefore (x-x)/((1-x))^(2)=9`
or `x^(2)=9+9x^(2)-18x`
or `8x^(2)-18x+g=0`
`therefore x=(3)/(2) or (3)/(4)`
Hence among the given options, the option` (3)"i.e.,0.75` is correct