`N_2 and H_2` are taken in 1:3 molar ratio in a closed vessel to attained the following equilibrium , `N_2(g)+3H_2(g) hArr 2NH_3(g)`
Find `K_p` for reaction at total pressure of 2P if `P_(N_2)` at equilibrium is `P/3`:

Options

A. (A) `(1)/(3P^(2)`
B. (B) `(4)/(3P^(2))`
C. (C) `(4P^(2))/(3)`
D. (D) none

Answer

B

Explanation

`N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)`
At equilibrium `(P)/(3) P . (P)/(3)+P+P_(NH_(3)=2P`
`P_(NH_(3))=(2P)/(3) K_(p)=((2P)/(3)xx(2P)/(3))/((P)/(3)xxP^(3))=(1)/(P^(4))(4)/(3) rArr K_(p)=(4)/(3P^(2))`