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The equilibrium constant for N(2)(g)+O(2...

The equilibrium constant for `N_(2)(g)+O_(2)(g)hArr2NO "is" K_(1)` and that for `NO(g)hArr(1)/(2)N_(2)(g)+(1)/(2)O_(2)(g)` is `K_(2). K_(1) "and" K_(2)` will be related as

A

`K_(1)=((1)/(K_(2)))^(2)`

B

`K_(1)=K_(2)^(2)`

C

`K_(2)=((1)/(K_(1)))^(2)`

D

`K_(2)=K_(1)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`N_(2)(g)O_(2)(g)overset(K_(1))(hArr)2NO`
Hence
`2NOhArrN_(2)+O_(2) K'=(1)/(K_(1)`
& for
`NOhArr(1)/(2)N_(2)+(1)/(2)O_(2) K"=sqrtK'=sqrt((1)/(K_(1)))=K_(2)`
`K_(2)=sqrt((1)/(K_(1)))`
`K_(2)^(2)=(1)/(K_(1))`
or `K_(1)=((1)/(K_(2)))^(2)`
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