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In the above question, alpha varies with...

In the above question, `alpha` varies with `(D)/(d)` according to:

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
B
`alpha=[(D-d)/(d)], alpha=[(D)/(d)-1], ((D)/(d))=alpha+1`.
`alpha=(D-d)/((n-1)d), alpha=(D-d)/(d),`

The point at which `alpha=0`.
` [(D)/(d)-1]=0 , " So ",((D)/(d))=1`
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