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For the reaction H(2)(g) + I(2)(g)hArr2H...

For the reaction `H_(2)(g) + I_(2)(g)hArr2HI(g)K_(c) = 66.9` at `350^(@)C` and `K_(c) = 50.0` at `448^(@)C` . The reaction has

A

`DeltaH=+"ve"`

B

`DeltaH=-"ve"`

C

`DeltaH="zero"`

D

`DeltaH "sign can not be determined"`

Text Solution

Verified by Experts

The correct Answer is:
B
`H_(2)(g)+I_(2)(g)hArr2HI(g)`
`"log"(K_(2))/(K_(1))=(DeltaH)/(2.303R)[(1)/(T_(1))-(1)/(T_(2)) : "log" (50)/(66.9)=(DeltaH)/(2.303R)[(1)/(623)-(1)/(721)]`
After calculation negative value of `DeltaH` is obtained.
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