Home
Class 11
CHEMISTRY
Densities of diamond and graphite are (3...

Densities of diamond and graphite are `(3.5g)/(mL)` and `(2.3g)/(mL)`.
`Delta_(7)H=-1.9(kJ)/("mole")`
Favourable conditions for formation of diamond are:

A

high pressure and low temperature

B

low pressure and high temperature

C

high pressure and high temperature

D

low pressure and low temperature

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    RESONANCE|Exercise Exercise-2 (Part-1)|28 Videos
  • CHEMICAL EQUILIBRIUM

    RESONANCE|Exercise Exercise-2 (Part-2)|23 Videos
  • CHEMICAL EQUILIBRIUM

    RESONANCE|Exercise Exercise-1 (Part-1)|38 Videos
  • CHEMICAL BONDING

    RESONANCE|Exercise Inorganic chemistry (Chemistry Bonding)|49 Videos
  • D & F-BLOCK ELEMENTS & THEIR IMPORTANT COMPOUNDS

    RESONANCE|Exercise Match the column|1 Videos

Similar Questions

Explore conceptually related problems

Densities of diamond and graphite are (3.5g)/(mL) and (2.3g)/(mL) . Delta_(r)H=-1.9(kJ)/("mole") Favourable conditions for formation of diamond are:

Densities of diamond and graphite are 3.5 and 2.3 g mL^(-1) , respectively. The increase of pressure on the equilibrium C_("diamond") hArr C_("graphite")

The densities of graphite and diamond are 22.5 and 3.51 gm cm^(-3) . The Delta_(f)G^(ɵ) values are 0 J mol^(-1) and 2900 J mol^(-1) for graphite and diamond, respectively. Calculate the equilibrium pressure for the conversion of graphite into diamond at 298 K .

At 5xx10^(4) bar pressure density of diamond and graphite are 3 g//c c and 2g//c c respectively, at certain temperature 'T' .Find the value of DeltaU-DeltaH for the conversion of 1 mole of graphite to 1 mole of diamond at temperature 'T' :

At 500 kbar pressure density of diamond and graphite are 3 "g"//"cc" and 2 "g"//"cc" respectively, at certain temperature T. Find the value of |DeltaH-DeltaU| ("in kJ"//"mole") for the conversion of 1 mole of graphite 1 mole of diamond at 500 kbar pressure. (Given : 1 "bar" = 10^(5) "N"//"m"^(2))

Delta_(f) H of graphite is 0.23 kJ mol^(-1) and Delta_(f) H of diamond is 1.896 kh mol^(-1) . Delta H_(transition) from graphite to diamond is

RESONANCE-CHEMICAL EQUILIBRIUM-Exercise-1 (Part-2)
  1. The value of DeltaG^(@) for a reaction in aqueous phase having K(c)=1,...

    Text Solution

    |

  2. The effect of temperature on equilibrium constant is expressed as(T(2)...

    Text Solution

    |

  3. For the reaction, CO(g)+H(2)O(g)hArrCO(2)(g)+H(2)(g), at a given tem...

    Text Solution

    |

  4. Given the following reaction at equilibrium N(2)(g) + 3H(2)(g)hArr2NH(...

    Text Solution

    |

  5. The equilibrium SO(2)Cl(2)(g)hArrSO(2)(g)+Cl(2)(g) is attained at 25^(...

    Text Solution

    |

  6. Densities of diamond and graphite are (3.5g)/(mL) and (2.3g)/(mL). ...

    Text Solution

    |

  7. Introduction of inert gas (at the same temperature) will affect the eq...

    Text Solution

    |

  8. The equilibrium SO(2) CI(2) (g) hArr SO(2)(g) +CI(2)(g) is attain...

    Text Solution

    |

  9. An equilibrium mixture in a vessel of capacity 100 litre contain 1 "mo...

    Text Solution

    |

  10. For the equlibrium H(2)O(s)hArrH(2)O(l) which of the following stateme...

    Text Solution

    |

  11. A reaction in equilibrium is respresnt by the following equation 2A((s...

    Text Solution

    |

  12. For the reaction, CO(g)+H(2)O(g)hArrCO(2)(g)+H(2)(g), at a given tem...

    Text Solution

    |

  13. Two equilibrium ABhArrA^(o+)+B^(Θ) and AB+B^(Θ)hArrAB(2)^(Θ) are sim...

    Text Solution

    |

  14. In the preceeding problem, if[A^(+)]"and"[AB(2)^(-)] "are" y "and" x r...

    Text Solution

    |

  15. The following two reactions: i. PCl(5)(g) hArr PCl(3)(g)+Cl(2)(g) ...

    Text Solution

    |

  16. C(s)+CO(2)(g)hArr2CO(g) K(p)=1atm CaCO(3)(s)hArrCaO(s)+CO(2)(s) K(p)...

    Text Solution

    |

  17. CaCI(2).6H(2)O(s)hArrCaCI(2)(s)+6H(2)O(s) K(p)=6.4xx10^(-17) atm^(6)...

    Text Solution

    |

  18. A(s)hArrB(g)+C(g) K(p(1))=36 atm^(2) E(s)hArrB(g)+D(g) K(p(2))=64atm...

    Text Solution

    |

  19. In a closed container following equilibrium will be attained- A(s)+B...

    Text Solution

    |

  20. 2NH(3)(g)hArrN(2)(g)+3H(2)(g) in a V lit container total x mol at eq. ...

    Text Solution

    |