If `K_(1),K_(2),K_(3)` are equilibrium constant for formation of `AD,AD_(2),AD_(3)` respectively as follows `A+DhArrD,AD+DhArrAD_(2),AD_(2)+DhArrAD_(3)`. Then equilibrium constant `'K' "for" A+3DhArrAD_(3)` is related as

Options

A. `K_(1)+K_(2)+K_(3)=K`
B. `logK_(1)+logK_(2)+logK_(3)=logK`
C. `K_(1)+K_(2)=K_(3)+K`
D. `logK_(1)+logK_(2)=logK_(3)+logK`

Answer

B

Explanation

`A+dhArrAD,K_(1)`
`AD+DhArrAD_(2),K_(2)`
`(AD_(2)+DhArrAD_(3),K_(3))/(A+3DhArrAD_(3),K)`
As we know that `K=K_(1).K_(2).K_(3)`
Or, `logK=logK_(1)+logK_(2)+logK_(3)`