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The equilibrium constant for the reactio...

The equilibrium constant for the reaction `N_(2)+3H_(2)hArr2NH_(3) "is" 70` at a certain temperature. Hence, equilibrium constant for the reaction `NH_(3)hArr(1)/(2)N_(2)+(3)/(2)H_(2)` of the same temperature will be approximately

A

`1.4xx10^(-2)`

B

`1.2xx10^(-1)`

C

`2.0xx10^(-4)`

D

`2.9xx10^(-2)`

Text Solution

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The correct Answer is:
B
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  6. Increased pressure shifts the equilibrium of the reaction: N(2)(g)+3H(...

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  8. Which of the following changes the value of the equilibrium constant ?

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  17. At 445^(@)C,K(c) for the following reaction is 0.020. 2HI(g)H(2)(g)+...

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