The equilibrium constant `K_(c)` for the reaction,
`2NaHCO_(3)(s)hArrNa_(2)CO_(3)(s)+CO_(2)(g)+H_(2)O(g)`

Write the unit of equlibrium constant (K_(c)) for the given reaction. BaCO_(3)(s)hArrBaO(s)+CO_(2)(g)

At a certain temperature , the equilibrium constant (K_(c)) is 4//9 for the reaction : CO(g)+H_(2)O(g) hArr CO_(2)(g)+H_(2)(g) If we take 10 mole of each of the four gases in a one - litre container, what would be the equilibrium mole percent of H_(2)(g) ?

Write the expression for equilibrium constant K_(p) for the reaction, 3 Fe (s) + 4 H_(2)O (g) hArr Fe_(3)O_(4) (s) + 4 H_(2)(g).

The equilibrium constant for the reaction Zn(s)+CO_(2)(g)hArrZnO(s)+CO(g) is

If 2H_(2)O_((g))hArr2H_(2(g))+O_(2(g)), K_(1)=2.0xx10^(-13) 2CO_(2(g))hArr2CO_((g))+O_(2(g)), K_(2)=7.2xx10^(-12) Find the equilibrium constant for the reaction CO_(2(g))+H_(2(g))hArrCO_((g))+H_(2)O_((g))

Write the unit of equilibrium constant (K_c) for the given reaction. BaCO_3(s) hArr BaO(s) +CO_2(g)

Form the given data of equilibrium constants of the following reactions: CuO(s)+H_(2)(g)hArrCu(s)+H_(2)O(g),K=67 CuO(s)+CO(g)hArrCu(s)+CO_(2)(g),K=490 Calculate the equilibrium constant of the reaction, CO_(2)(g)+H_(2)(g)hArrCu(s)+CO_(2)(g)+H_(2)O(g)

The equilibrium constant for the following reactions at 1400 K are given. 2H_(2)O(g)hArr2H_(2)(g) + O_(2)(g) , K_(1)=2.1×x10^(-13) 2CO_(2)(g) hArr2CO(g)+O_(2)(g),K_(2) = 1.4 x× 10^(-12) Then, the equilibrium constant K for the reaction H_(2)(g) + CO_(2)(g)hArrCO(g) + H_(2)O(g) is

At a certain temperature , the following reactions have the equilibrium constants as shown below: S(s)+O_(2)(g)hArrSO_(2)(g),K_(c)=5xx10^(52) 2S(s)+3O_(2)(g)hArr2SO_(3)(g),K_(c)=5xx10^(29) what is the equilibrium constant K_(c) for the reaction at tahea same temperature? 2SO_(2)(g)+O_(2)(g)hArr2SO_(3)(g)